Yes, this can be solved with grep using the regular expression ^[0-9].*[^\\\\d]$. Here's an example command:

grep '^[0-9].*[^\\\\d]$' file.txt

This will print all lines in file.txt that start with a digit character and end with a non-digit character.

Yes, you can solve this using AWK. Here's an example command:

awk -F, '{max=$1; for(i=2;i<=NF;i++) if($i>max) max=$i; print "Line " NR ": " max}' file.txt

This command sets the field separator to a comma with -F,. For each line of the file, it initializes max to the first number in the line, then iterates through the remaining numbers and updates max if a larger number is found. Finally, it prints the line number and the maximum number found.

Yes, this can be done in SED with the following command:

sed -E 's/[[:space:]]{2,}/ /g' file.txt

This command uses the regular expression [[:space:]]{2,} to match any group of at least two consecutive whitespace characters (spaces, tabs, etc.). It then replaces each match with a single space character. The -E flag is used to enable extended regular expressions. The g flag is used to replace all matches on each line. Replace file.txt with the name of your input file.

This command uses grep to search for lines in inputgrep.txt that start with a digit. The ^ character matches the start of a line, [0-9] matches any digit, and .* matches any number of characters after the digit.

This command uses grep to search for lines in inputgrep.txt that start with a digit. The ^ character matches the start of a line, [0-9] matches any digit, and .* matches any number of characters after the digit. The [^\\\\\\\\d] specifies the character at the end of the line should not be a digit. The \\\\\\\\d is used to represent digit characters in regular expressions.

This command uses grep to search for lines in inputgrep.txt that start with a digit and end with a non-digit character. The ^ character matches the start of a line, [0-9] matches any digit, and .* matches any number of characters after the digit. The [^\\\\\\\\\\\\\\\\d] specifies the character at the end of the line should not be a digit. The \\\\\\\\\\\\\\\\d is used to represent digit characters in regular expressions.

What does this do sed -E 's/[[:space:]]{2,}/ /g' inputsed.txt

This command uses sed to replace any group of two or more consecutive whitespace characters with a single space character in the file "inputsed.txt". The regular expression [[:space:]]{2,} matches any group of two or more whitespace characters (spaces, tabs, etc.), and the replacement string " " replaces each match with a single space character. The -E flag is used to enable extended regular expressions.

This AWK command reads the file "inputawk.txt" and uses the comma character as the field separator with -F,. For each line, it initializes max to the first field in the line, then iterates through the remaining fields and updates max if a larger field is found. Finally, it prints the line number (NR) and the maximum field value found. The output will be printed in the format "<line number>: <maximum value>".

Yes, this can be done in grep with the following command:

grep '^[0-9].*[^[:digit:]]$' file.txt